
Dayv O. answered 02/24/23
Caring Super Enthusiastic Knowledgeable Calculus Tutor
the d.e. is very close to being an exact equation.
The technique for solving not so hard.
Are you sure the d.e. typed is without a typo?
Madison C.
asked 02/24/23Please provide a solution thank you!
Dayv O. answered 02/24/23
Caring Super Enthusiastic Knowledgeable Calculus Tutor
the d.e. is very close to being an exact equation.
The technique for solving not so hard.
Are you sure the d.e. typed is without a typo?
Aime F. answered 02/24/23
Experienced University Professor of Mathematics & Data Science
Notice that the problem is equivalent to
dx = (y – 2x)dt,
dy = (x + y – c)dt
for some auxiliary variable t on which (x,y) depends, and c = 1.
If you diagonalize the matrix (aij) with a₁₁ = –2, a₁₂ = a₂₁ = a₂₂ = 1, you can get (x(t),y(t)) as a function of t, c and initial condition (x(0),y(0)).
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.