Dayv O. answered 02/24/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
the d.e. is very close to being an exact equation.
The technique for solving not so hard.
Are you sure the d.e. typed is without a typo?
Madison C.
asked 02/24/23Please provide a solution thank you!
Dayv O. answered 02/24/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
the d.e. is very close to being an exact equation.
The technique for solving not so hard.
Are you sure the d.e. typed is without a typo?
Aime F. answered 02/24/23
Experienced University Professor of Mathematics & Data Science
Notice that the problem is equivalent to
dx = (y – 2x)dt,
dy = (x + y – c)dt
for some auxiliary variable t on which (x,y) depends, and c = 1.
If you diagonalize the matrix (aij) with a₁₁ = –2, a₁₂ = a₂₁ = a₂₂ = 1, you can get (x(t),y(t)) as a function of t, c and initial condition (x(0),y(0)).
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