Write the complete nuclear equation for the bombardent of a Be9 atom with an 𝛼 particle to yield B12 . Show the atomic number and mass number for each species in the equation

Answer 1

I'm guessing that the product of this reaction should be C-12 and not B-12.

An 𝛼 particle is essentially a helium nucleus: ⁴₂He, so we can write the following:

⁹₄Be + ⁴₂He ==> ¹₀n + ¹²₆X

X would be Carbon (atomic number 6, atomic mass 12)

So, answer should be ⁹₄Be + ⁴₂He ==> ¹₀n + ¹²₆C

Be-9 + alpha particle ==> neutron + C-12

OR

⁹₄Be + ⁴₂He ==> ¹²₅B + ¹₁H