Science-Chemistry

Question

What is ∆G for a reaction where ∆G° = 3.2 kJ/mol and Q = 3.3 at 295 K? (R = 8.314 J/mol ･ K)

Answer 1

∆G = ∆Gº + RT ln Q

∆G = ?

∆Gº = 3.2 kJ / mol

R = 8.314 J / mol K = 0.008314 kJ / mol K (NOTE: change units of R to agree with those of ∆Gº)

T = 295K

Q = 3.3

∆G = 3.2 + (0.008314)(295) ln 3.3

∆G = 3.2 + 2.93

∆G = 6.1 kJ / mol