Angie R.

asked • 02/23/23

please help I do not get this

An object is thrown upward at a speed of 51 feet per second by a machine from a height of 3 feet off the ground. The height  of the object after t seconds can be found using the equation s(t)=-16t2+v0t+s0, where v0 is the initial velocity and s0 is the initial height. Give all numerical answers to 2 decimal places.

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