How many grams of Na2SO4 will be produced if you start with 158 grams of NaOH?

Answer 1

The reaction you are probably dealing with is the neutralization reaction of NaOH + H2SO4

2NaOH + H₂SO₄ ==> Na₂SO₄ + 2H₂O .. balanced equation

molar mass NaOH = 40 g / mol

158 g NaOH x 1 mol NaOH / 40 g = 3.95 mols NaOH

moles Na₂SO₄ formed = 3.95 mols NaOH x 1 mol Na₂SO₄ / 2 mol NaOH = 1.975 mols Na₂SO₄

mass Na₂SO₄ formed = 1.975 mols Na₂SO₄ x 142 g / mol = 280. g Na₂SO₄ produced

Answer 2

To determine the number of grams of Na2SO4 that will be produced from 158 grams of NaOH, we need to first write the balanced chemical equation for the reaction between NaOH and Na2SO4:

2 NaOH + Na2SO4 → Na2SO4 + 2 H2O

From the balanced equation, we can see that the reaction produces an equal number of moles of Na2SO4 and NaOH. Therefore, we need to first convert the given mass of NaOH to moles:

Molar mass of NaOH = 23.0 g/mol + 16.0 g/mol + 1.0 g/mol = 40.0 g/mol

Number of moles of NaOH = 158 g / 40.0 g/mol = 3.95 mol

Since the reaction produces an equal number of moles of NaOH and Na2SO4, we can say that 3.95 moles of Na2SO4 will be produced. To convert this to grams, we can use the molar mass of Na2SO4:

Molar mass of Na2SO4 = 22.99 g/mol + 32.06 g/mol + 4(15.99 g/mol) = 142.04 g/mol

Mass of Na2SO4 produced = 3.95 mol × 142.04 g/mol = 561.178 g

Therefore, starting with 158 grams of NaOH will produce 561.178 grams of Na2SO4.