Patrick L. answered 8d
P(winning ticket) = 0.30
You also want the probability of not having a winning ticket in order to solve this probability.
P(not winning ticket) = 1 - 0.30 = 0.70
The probability of not having a winning ticket for 6 days is as follows: (0.70)^6 = 0.117649
P(at least one winning ticket) = 1 - P(no winning ticket for 6 days) = 1 - 0.117649 = 0.882351 ≈ 0.8824
The probability that Jorge has won at least one prize is about 0.8824.