A 210.4g hydrate of Epsom Salt, MgSO4×H2O was hested ip, the water was released, abd the final anhydrate mass was 120.4 g. What is the formula of this hydrate

Answer 1

First, calculate the mass of H₂O released:

210.4 g - 120.4 g = 90.0 g H₂O

Convert this to moles of H₂O:

90.0 g H₂O x 1 mol H₂O / 18 g = 5 moles H₂O

This tells us that 5 moles of H₂O = XH₂O in the formula

Formula of the hydrate = MgSO₄ • 5H₂O (magnesium sulfate pentahydrate)