J.R. S. answered 02/21/23
Ph.D. University Professor with 10+ years Tutoring Experience
The order of the rate law is the sum of the exponents. In this case since both [A] and [B] are raised to the first power, the order = 2. So for a second order reaction, the units for k (rate constant) are M-1s-1 or any units of reciprocal concentration reciprocal time.
This can be calculated as follows, using M as concentration and sec as time.
Rate = k[A][B]
M/sec = k [M][M]
k = M/sec / M2
k = M-1s-1

J.R. S.
02/22/23
Hailey W.
Thank you! That makes a lot more sense using M as concentration and seconds as time.02/21/23