J.R. S. answered 02/21/23
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What are you looking for? Are you supposed to find the pH? If so, it's the negative log of [H3O+]
pH = -log 8x10-6 = 5.10
If you are trying to find [OH-] it is
[OH-] = 1x10-14 / 8x10-6 = 1.25x10-9 M