J.R. S. answered 02/19/23
Ph.D. University Professor with 10+ years Tutoring Experience
(a). 0.30 M HNO3
HNO3 (strong acid) ==> H+ + NO3-
[H+] = 0.30 M
[NO3-] = 0.30 M
pH = -log [H+] = -log 0.30 = 0.52
(b). 0.30 M NaOH (strong base) ==> Na+ + OH-
[Na+] = 0.3 M
[OH-] = 0.30 M
pOH = -log [OH-] = -log 0.30 = 0.52
pH = 14 - 0.52 = 13.48
(c). 4.2x10-3 M HClO4 (strong acid) ==> H+ + ClO4-
[H+] = 4.2x10-3 M
[ClO4-] = 4.2x10-3 M
pH = -log [H+] = -log 4.2x10-3 M = 2.38
(d). 2.9x10-4 M Ca(OH)2 (strong base) ==> Ca2+ + 2OH-
[Ca2+] = 2.9x10-4 M
[OH-] = 2 x 2.9x10-4 M = 5.8x10-4 M
pOH = -log [OH-] = -log 5.8x10-4 M = 3.24
pH = 14 - 3.24 = 10.76
(e). 1.0 M NaCl (neutral salt) ==> Na+ + Cl-
[Na+] = 1.0 M
[Cl-] = 1.0 M
pH = 7
(f). 0.10 M KNO3 (neutral salt) ==> K+ + NO3-
[K+] = 0.10 M
[NO3-] = 0.10 M
pH = 7