If you react excess CuSO4 and 24.0 mL of NH3 (density = ), how many moles of Cu(NH3)4SO4 can be produced?

Question

If you react excess CuSO₄ and 24.0 mL of NH₃=), how many moles of Cu(NH₃)₄SO_4.Density=(0.860g/1 ml)

Please Show work, thank you.

Answer 1

Write a correctly balanced equation for the reaction taking place:

CuSO₄(aq) + 4NH₃ ==> Cu(NH₃)₄SO₄

Using the density of NH₃ as 0.860 g / ml, and the molar mass of NH₃ of 17 g / mol, calculate moles of NH₃:

mols NH₃ = 24.0 ml x 0.860 g / ml x 1 mol / 17 g = 1.21 mols NH₃ present

Use the stoichiometry of the balanced equation to find moles Cu(NH₃)₄SO₄ formed:

1.21 mols NH₃ x 1 mol Cu(NH₃)₄SO₄ / 4 mol NH₃ = 0.303 mols Cu(NH₃)₄SO₄