A samp;e of an alloy has a specific heat of 2.4

Question

a sample of an alloy that has a specific heat of 2.4 J/g*K is heated from 293K to 343K it absorbs 45.8kj of energy what is the mass of the sample in grams?

Answer 1

Use q = mC∆T

q = heat = 45.8 kJ = 45800 J

m = mass = ?

C = specific heat = 2.4 J/gº

∆T = change in temperature = 343 - 293 = 50º

Solving for m ...

m = q /(C)(∆T) = 45800 J / (2.4 J/gº)(50º)

m = 382 g = 380 g (to 2 sig. figs.)