Andrew K. answered 02/18/23
Statistics professional with 7+ years of experience
Sample mean = 275/33 = 8.33. To exceed 275 minutes, each jet on average will need to take more than 8.33 minutes
(8.33-8.3) / (3.5/sqrt(33)) = .03 / .6092 = .0492
p(Z > .092) ~ .4801
There is a 48% probability that the takeoff time for 33 jets will exceed 275 minutes.
Give the other one a go and let me know if you have questions!