J.R. S. answered 02/15/23
Ph.D. University Professor with 10+ years Tutoring Experience
4Al(s) + 3O2(g) ⇌ 2Al2O3(s)
∆Gº = ∆Hº - T∆Sº
∆Hº = -1669.8 kJ/mol
∆Sº = 50.99 - (28.3 + 205) = 50.99 - 233.3 = -182.3 J/mol = -0.1823 kJ/mol
∆Gº = -1669.8 - (273)(-0.1823) = -1669.8 + 49.8
∆Gº = -1620 kJ/mol
Because ∆Gº is negative, the reaction is spontaneous and products are favored.