equilibrium homework help

Question

Consider the reaction below: 2 CO(g) + O₂(g) ⇌ 2 CO₂(g) If Kc is 2.24 × 10²² at 1273.0 °C, calculate Kp at the same temperature. (R = 0.08206 L･atm/mol･K.)

Answer 1

2 CO(g) + O₂(g) ⇌ 2 CO₂(g)

The relationship between Kp and Kc is...

Kp = Kc(RT)^∆n

where R = gas constant = 0.08206 Latm/Kmol

T= temperature in Kelvin = 1273C + 273 = 1546K

∆n = change in number of moles of gas = 2 - 3 = -1

Kp = 2.24x10²² (0.0821 x 1546)^-1

Kp = 2.24x10²² x 1 / 127 = 2.24x10²² x 0.00788

Kp = 1.77x10²⁰

(be sure to check all of the math)