J.R. S. answered 02/14/23
Ph.D. University Professor with 10+ years Tutoring Experience
∆T = imK
∆T = freezing point change = 8.07º
i = van't Hoff factor = 1 for vitamin K since it is a non electrolyte
m = molality = mols Vit K / kg camphor = ?
K = freezing constant for camphor = should be given in the question. Looked it up & it is 40ºC/m
Solving for molality (m);
m = ∆T /(i)(K)
m = 8.07 / (1)(40)
m = 0.20175 mols Vit K / kg camphor
Since we have 25.0 g camphor, we can determine moles of Vit K present:
25.0 g camphor x 1 kg / 1000 g = 0.025 kg
0.20175 mols / kg x 0.025 kg = 0.00504 mols Vit K
Since molar mass = grams / moles, we now have sufficient info to calculate molar mass:
molar mass = 2.41 g / 0.00504 mols = 478 g / mol