J.R. S. answered 02/09/23
Ph.D. University Professor with 10+ years Tutoring Experience
2HNO3(aq) + Ba(OH)2(aq) ==> 2H2O(l) + Ba(NO3)2(aq) .. balanced equation
moles Ba(OH)2 used = 43.5 ml x 1 L / 1000 mls x 0.150 mols / L = 0.006525 moles
moles HNO3 present = 0.006525 mols Ba(OH)2 x 2 mols HNO3 / mol Ba(OH)2 = 0.01305 mols
Concentration HNO3 = moles / L = 0.01305 mols / 0.110 L = 0.119 M (3 sig. fgis.)