Consider the given reaction. A(aq) + B(s) ⇌ C(aq) K = 9.40

Question

Consider the given reaction.

A(aq) + B(s) ⇌ C(aq) K = 9.40

Suppose 13.9 mol A reacts with excess B in 7.90 L of solution. Calculate the concentration of C at equilibrium.

[C] = _____ M

Answer 1

A(aq) + B(s) ⇌ C(aq) K = 9.40

13.9 mol A / 7.90 L = 1.76 M

A(aq) + B(s) ⇌ C(aq)

1.76......xs..........0........Initial

-x.....................+x.......Change

1.76-x................x.........Equilibrium

K = [C] / [A] (B is not included since it is a solid)

9.40 = [x] / [1.76-x]

16.5 - 9.40x = x

8.40x = 16.5

x = [C] = 1.97 M