At 403 K, this reaction has a Kc value of 0.0392.

Question

At 403 K, this reaction has a Kc value of 0.0392.

X(g) + 3 Y(g) ⇌ 2Z(g)

Calculate Kp at 403 K. Note that the pressure is in unites of atmosphere (atm).

Kp =

Answer 1

Kp = Kc(RT)^∆n

Kp = ?

Kc = 0.0392

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = 403K

∆n = change in moles of gas from reactants to products = 2 - 4 = -2

Solving for Kp:

Kp = 0.0392 x (0.0821*403)^-2 = (0.0392)(33.09)^-2

Kp = (0.0392)(0.1739)

Kp = 0.00682

(Be sure to check all of the math)