How many moles of O2 can be produced by letting 8.00 moles of KClO3 react?

Question

Need help with this one im stuck on what too do.

Answer 1

The first thing you have to do is to write the correctly balanced equation for the decomposition of KClO3:

2KClO₃ ==> 2KCl + 3O₂ .. balanced equation

Next, use dimensional analysis and the stoichiometry (mole ratio) of the balanced equation:

8.00 mols KClO₃ x 3 mols O₂ / 2 mols KClO₃ = 12 moles O₂