Find K for ΔG° of -5.2 kJ/mol at 25°C

Question

Given a ΔG° of -5.2 kJ/mol at 25°C, calculate the corresponding K.

[R = 8.314 J/K∙ mol]

Answer 1

∆Gº = -RT ln K

-5.2 kJ / mol = -(0.008314 kJ/Kmol)(298K) ln K (note: changed units of R to agree with those of ∆Gº)

ln K = -2.0988

K = 0.123