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Question

About 9% of the population has a particular genetic mutation. 300 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 300. Round your answer to three decimal places

Answer 1

We'll use the proportion given as a binomial distribution probability for the sample. With n being the number of the sample the mean will be np with a standard deviation of sqrt(np(1-p)) which is nσ_p.

You can substitute p=.9 and n=300 into the expression for standard deviation.

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