J.R. S. answered 02/06/23
Ph.D. University Professor with 10+ years Tutoring Experience
Methane = CH4
Molar mass CH4 = 16.0 g / mole
CH4 + 2O2 ==> CO2 + 2H2O .. balanced equation for combustion of methane
moles CH4 used = 7.50x10-3 g x 1 mol / 16.0 g = 4.6875x10-4 moles
moles H2O produced = 4.6875x10-4 moles CH4 x 2 mol H2O / mol CH4 = 9.375x10-4 mols H2O
mass H2O = 9.375x10-4 mols H2O x 18.0 g H2O / mol = 0.0169 g H2O (3 sig. figs.)