Earth (mass = 6.0 x 10^27 g) moving through space at 3.5 x 10^4 M/S

Question

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Answer 1

I the comment section, I noted that you hadn't asked a question. If you are seeking the kinetic energy of the earth, then the following might apply:

KE = 1/2 mv²

KE = kinetic energy = ?

m = mass in kg = 6.0x10²⁷ g x 1 kg / 1000 g = 6.0x10²⁴ kg

v = velocity in m/s = 3.5x10⁴ m/s

KE = 1/2 (6.0x10²⁴ kg)(3.5x10⁴ m/s)²

KE = 3.7x10³³ kg-m²/s² = 3.7x10³³ joules