I NEED THIS QUICK

Question

Quadrilateral EFGH has vertices at E(2,1) F(7,2) G(4,9) and H(–1,7). Is EFGH a parallelogram? 

Answer 1

E(2,1) F(7,2), G(4,9) H(-1,7)

EF has slope = (2-1)/(7-2)= 1/5

FG has slope = (9-2)/(4-7) = -7/3=-2 1/3

GH has slope = (9-7)/4+1) = 2/5

EH has slope = (7-1)/(-1-2) = 6/-3 = -2

EG has slope = (9-1)/(4-2)= 8/2 = 4

FH has slope = (7-2)/-1-7) = 5/-8 = -5/8

to be a parallelogram opposite sides must be parallel

none of the sides in EFGH have parallel sides

if they did, they'd have equal slopes

none of the slopes are equal

it may help to plot the pionts, connect the points and see if it looks like a parallelogram. sides FG and EH are close to parallel, -2 and - 2 1/3

GH and Ef are also close to parallel, 1/5 and 2/5. You could say it's almost a parallelogram, but it's not.