J.R. S. answered 02/02/23
Ph.D. University Professor with 10+ years Tutoring Experience
Anytime you have a precipitate formed, you can simply write the net ionic equation as the formation of that precipitate. So, for the current problem, the precipitate is silver chloride, AgCl.
Net ionic equation: Ag+(aq) + Cl-(aq) ==> AgCl(s)
Looking at the full explanation, we will first write the molecular equation, followed by the compete ionic equation, and finally, the net ionic equation.
molecular equation: AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)
complete ionic eq: Ag+(aq) + NO3-(aq) + K+(aq) + Cl-(aq) ==> AgCl(s) + K+(aq) + NO3-(aq)
net ionic equation: Ag+(aq) + Cl-(aq) ==> AgCl(s) (note: K+ and NO3- are spectator ions)