Find the equation of a line y=4/3x+4 that passes through the point of 3, -7

Answer 1

The equation of the line that passes through the point (3, -7) with a slope of 4/3 is:

y = (4/3)x + b

where b is the y-intercept. To find the y-intercept, we can use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

where (x1, y1) is the given point, and m is the slope. Substituting the given values into this formula, we get:

y - (-7) = (4/3)(x - 3)

Solving for y, we get:

y = (4/3)x + (-7 + (4/3) * 3)

y = (4/3)x + 4

So the equation of the line is:

y = (4/3)x + 4

Answer 2

4/3=(y+7)/(x-3)

This is point-slope form.