Edward C. answered 03/24/15
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Caltech Grad for math tutoring: Algebra through Calculus
On the 1st draw we have P(A) = 4/7 and P(O) = 3/7
If the 1st draw is A then on the 2nd draw we have P(A) = 3/6 and P(O) = 3/6
If the 1st draw is O then on the 2nd draw we have P(A) = 4/6 and P(O) = 2/6
P(AA) = (4/7)*(3/6) = 12/42 = 2/7
P(AO) = (4/7)*(3/6) = 12/42 = 2/7
P(OA) = (3/7)*(4/6) = 12/42 = 2/7
P(OO) = (3/7)*(2/6) = 6/42 = 1/7
P(O>=1) = 1 - P(AA) = 1 - 2/7 = 5/7
P(different) = P(AO) + P(OA) = 2/7 + 2/7 = 4/7
P(draw 2 = O) = P(AO) + P(OO) = 2/7 + 1/7 = 3/7
P(draw 2=O | different) = (2/7) / (4/7) = 1/2
c) and d) are not independent. If they were then d) and e) would have the same probability
E(#O) = (2/7)*0 + (2/7 + 2/7)*1 + (1/7)*2 = 5/7