GIVEN: FD congruent to FE, GF bisects <DFE. PROVE: G is midpoint of DE

Question

its a triangle

D is on the bottom left

G is in the middle on the bottom

E is on the bottom right

F is at the top of the triangle

Answer 1

FD ≅ FE (given).

FG bisects <F (given)

<DFG ≅ < EFG (definition of ANGLE BISECTOR)

FG ≅ FG (reflexive property)

triangle DFG ≅ EFG (SAS)

DG ≅ EG (CPCTC)

G is the midpoint of DE (definition of MIDPOINT)