A sample of NH₃ was placed in a container and heated to 470.0 °C, and the following reaction was allowed to come to equilibrium.

Question

A sample of NH₃ was placed in a container and heated to 470.0 °C, and the following reaction was allowed to come to equilibrium. N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g) The equilibrium concentrations were found to be [NH₃] = 1.26 M, [N₂] = 0.868 M, and [H₂] = 2.60 M. What is the equilibrium constant, Kc, for the reaction?

Answer 1

N₂(g) + 3H₂(g) <===> 2NH₃(g) .. balanced equation

Kc = [NH₃]² / [N₂][H₂]³

Now, simply plug in the given values, and solve:

Kc = [1.26]² / [0.868][2.60]³ = 1.588 / 15.26

Kc = 0.104