Consider the reaction below: 2 CO(g) + O₂(g) ⇌ 2 CO₂(g)

Question

Consider the reaction below: 2 CO(g) + O₂(g) ⇌ 2 CO₂(g) If Kc is 2.24 × 10²² at 1273.0 °C, what is Kp at the same temperature? (R = 0.08206 L･atm/mol･K.)

Answer 1

2 CO(g) + O₂(g) <==> 2 CO₂(g) .. balanced equation

Use the expression Kp = Kc(RT)^∆n

Kp = ?

Kc = 2.24x10²²

R = 0.08206 Latm/molK

T = 1273.0ºC + 273 = 1546K (note to convert to K)

∆n = change in moles = 2 - 3 = -1

Solving for Kp, we have ...

Kp = 2.24x10²² (0.08206 x 1546)^-1

Kp = 2.24x10²² * 0.00788

Kp = 1.77x10²⁰