
David W. answered 01/25/23
Experienced Prof
Method 1: Diagram
Group 1: xxxxxxxxxxxxxxx
Group 2: xxxxxxxxxxxxxxx + 20
Group 3: xxxxxxxxxxxxxxx + 20
xxxxxxxxxxxxxxx + 20
Group 4: xxxxxxxxxxxxxxx + 20
xxxxxxxxxxxxxxx + 20 + 10
Total = 6 * xxxxxxxxxxxxxxx + 110 = 1700
xxxxxxxxxxxxxx = 1590 / 6 = 265
Group 1: 265
Group 2: 285
Group 3: 570
Group 4: 580
Total: 1700
Method 2: Algebraic Equations
Total – 1700
a = count in Group 1
b = count in Group 2
c = count in Group 3
d = count in Group 4
Note that we may write equations in terms of a:
b = a + 20
c = 2 * b = 2 * (a + 20)
d = c + 10 = 2 * (a + 20) + 10
total = a + b + c + d = 1700
a + (a + 20) + (2 * (a + 20)) + (2 * (a + 20) + 10 = 1700
6 * a + 110 = 1700
a = 1590 / 6
a = 265
Now that a is known, it is easy to find b, c, and d,
The two methods use similar use of the total and the relationship of each quantity on the quantity in the first group (a),