J.R. S. answered 01/25/23
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331 mg x 1 g / 1000 mg x 1 atom / 1.59x10-22 g = 2.08x1021 atoms of molybdenum
Olivia R.
asked 01/24/23J.R. S. answered 01/25/23
Ph.D. University Professor with 10+ years Tutoring Experience
331 mg x 1 g / 1000 mg x 1 atom / 1.59x10-22 g = 2.08x1021 atoms of molybdenum
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