Bruce H. answered 01/22/23
Mathematician with teaching and research experience in Statistics
For this question I used the normalCDF function on the TI-83 and plugged in the -1E99 for the lower bound and -1.63636 for the upper bound. Which returned a probability of .0509.
-1.63636 was found by converting the distribution to the standard normal by saying (28.5-15)/8.25 = 1.63636.
You could also look this value up on a z-table that gives the normal distribution probabilities.
A sample of 5 kittens would then have 5(.0509)=.2544 kittens dangerously underweight.
Chloe M.
I have a z-score probability table and I got -3.6585 as the z-score. It wasn't on the table so I got stuck. Thank you01/22/23