J.R. S. answered 01/21/23
Ph.D. University Professor with 10+ years Tutoring Experience
Molecular weight (molar mass) = grams / moles. We know the grams (7.0 mg = 7.0x10-3 g), so we need to find the moles.
Use the Beer Lambert Law: A = ϵcl
A= absorbance = 0.553
ϵ = extinction coefficient = 1.07x104 cm-1M-1
c = concentration = moles / L = ?
l = path length = 1 cm (not given in the question, but this is typical)
Solving for concentration in moles/L we have...
0.553 = (1.07x104 cm-1M-1)(c)(1)
C = 5.17x10-5 M = 5.17x10-5 moles / L
Since we have 295 mls (0.295 L), we can find moles present:
5.17x10-5 moles / L x 0.295 L = 1.52x10-5 moles
Molecular weight (molar mass) = grams / moles = 7.0x10-3 g / 1.52x10-5 moles
Molecular weight (molar mass) = 463 g / mole