Cumulative review question plz help need by tmo

Question

1.Which equation represents a line through (3,1) and parallel to y=-2x-9

2.Segment AB has endpoints with coordinates A(1,2) and B(5,10). In simplest radical form,find the length of AB.

*All work must be shown

1.The vertex of an isosceles triangle is 12 less than twice the base angles.What is the measure of the vertex angle?

2.At what coordinates will a perpendicular bisector intersect with AB, if A(-5,-3) and B(5,-8)?

Answer 1

1. Equation of the line through (3,1) parallel to y=-2x-9..

The line we are seeking will have slope of -2, because parallel lines have the same slope.

y=-2x+b

Substituting the point (3,1): 1=-2(3) + b

1=-6+b

b=7

Final answer: y=-2x+7

2. Find the length of the segment from (1,2) to (5,10)

Use the distance formula d = SQR((x₂ - x₁)² + (y₂-y₁)²⁾

d=SQR((5-1)²+(10-2)²) = SQR(4²+8²) = SQR(16+64) = SQR(80)

SQR(80) = SQR(16*5) = 4SQR(5)

1. The vertex angle of an isosceles triangle is 12 less than 2 times a base angle. Find the measure

of the vertex angle.

The angles are x, and x, and 2x-12. They add up to 180.

x+x+2x-12=180 4x-12=180 4x=192 x = 48.

The angles are 48, 48, and 84 degrees.

The vertex angle is 84 degrees.

2 Where will the perpendicular bisector intersect the segment from (-5,-3) to (5,-8)?

Any bisector will intersect at the midpoint. To find the midpoint, average the x and y coordinates of

the endpoints . The midpoint is (0, -5.5)