How to solve for x on a right triangle.

Question

The hypotenuse 22 the other side 11√3 and the bottom line as x

Answer 1

x^2 = 22^2 - (11sqr3)^2= 484-121(3)=484-363= 121

x = sqr121 = 11

hypotenuse squared = sum of squares of the other 2 sides

h= a^2+b^2

b^2 = h^2-a^2 = 22^2-(11sqr3)^2= 121

b = sqr121 = 11