Enter the probability as a fraction. P(at least one green) =

Question

Suppose that you have 8 cards. 3 are green and 5 are yellow. The 3 green cards are numbered 1, 2, and 3. The 5 yellow cards are numbered 1, 2, 3, 4, and 5. The cards are well shuffled. Suppose that you randomly draw two cards, one at a time, and without replacement.



• G₁ = first card is green

• G₂ = second card is green

Answer 1

The best way to calculate P(at least one green) is to calculate 1-P(no green)

P(no green) = 5/8 x 4/7 with no replacement

P( at least one green) = 1 - 5/8 x 4/7

You can also use G₁ + G₂ (if G₂ means hitting green after missing green on 1st card). (3/8 + 5/8 x 3/7)

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