The probablility of x>1.26 is the area above 1.26 divided by the total area: Let the actual value of the y axis variable be c.
P = (2-1.26)c/(2c) = .74/2 = .37
Tatihana G.
asked 01/03/23The uniform distribution of a random variable XX is given in the figure below.
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From the figure, what is P(X≥1.26)P(X≥1.26)?
The probablility of x>1.26 is the area above 1.26 divided by the total area: Let the actual value of the y axis variable be c.
P = (2-1.26)c/(2c) = .74/2 = .37
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