J.R. S. answered 01/01/23
Ph.D. University Professor with 10+ years Tutoring Experience
2AgNO3(aq) + BaCl2(aq) ==> 2AgCl(s) + Ba(NO3)2(aq) .. balanced equation
The balanced equation tells us it takes 2 mols AgNO3 for each 1 mol BaCl2. Thus, if you have 2 mols of each, the AgNO3 will run out first, leaving 1 mol of BaCl2 unreacted. The limiting reactant is AgNO3.
For future problems of this nature, you can simply just divide the mols of each reactant by the corresponding coefficient in the balanced equation. Whichever value comes out less will represent the limiting reactant. For the current problem, this calculation would look like this...
For AgNO3: 2 mol AgNO3 / 2 = 1
For BaCl2: 2 mol BaCl2 / 1 = 2
Since 1 is less than 2, that tells us that AgNO3 is the limiting reactant.