Christmas Day Present and challenge - find value of (-e^(2*(pi squared)^(1/(i*pi)

Question

present is,,,, e=-1^(1/(i*π))=-1^(-i/π)=-1^(-i*π^-1)

because e^(i*π)=-1 as one value of e^(i*π)

This value for e^(i*π) is same as Euler Formula/Identity

now, what is value of [-e^(2*π*π)]^(1/i*π) ?

Answer 1

the powers multiply leaving -e^2pi/i= -e^-i2pi

= -cos-2pi -isin-2pi

= -1 -i(0)

= -1