the probability mass function of a random variable X is given by pr(x)=cµ^2/x! x=1,2,3.where µ is some positive value .find the constant c. (1)p(x>2) .(2)pr(x=0)

Question



Answer 1

The probability mass function needs to add up to 1 when summed over all possible x:

cμ²(1 + 1/2 + 1/6) = 1

c = (1/μ²)(3/5), so p(x) = 3/(5*x!)

P(x>2) = P(3) = 3/(5*6) = 3/10

P(0) = 0 (Weird question - Is x=0 included? That would change the first part as well)

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