J.R. S. answered 12/13/22
Ph.D. University Professor with 10+ years Tutoring Experience
NaOH + HBr => NaBr + H2O .. balanced equation
mols NaOH used = (0.080 L)(0.670 mol/L) = 0.0536 mol
mols HBr present = 0.0536 b/c is 1:1 in equation
Molarity of HBr = 0.0536 mol/0.0255 L= 2.10 M