Hello Emily,
The general sample size formula that you want to use in this situation is
n = (Z^2 * o^2) / E^2
so it’s just a matter of identifying what those values would be for this question
from the values given we see that the tolerable error is 4 IQ pts, so that means E = 4. then Z = 1.645 since it’s a 90% level. finally o = 15.
putting that all together yields
n = (1.645^2 * 15^2) / 4^2
n = 608.855 / 16
n = 38.05
rounding up to the nearest whole number means that you would need to sample 39 professors in order to maintain these parameters, which seems like a reasonable amount! :)