Right Side trig with sec, csc, and cot

Question

Find the sin, cos, tan, sec, csc, and cot of angle A of a triangle, with an opposite angle of 6 and adjacent angle of 6. The hypotenuse is unknown.

Answer 1

assuming you really meant to say opposite & adjacent side, not opposite & adjacent angle of 6, then:

A = 45 degrees or pi/4

sinA = sqr2/2

cscA = 2/sqr2=sqr2

cosA = sqr2/2

secA = 2/sqr2= sqr2

tanA =1

cotA =1

hypotenuse = 6sqr6 = square root of the sum of squares of the two other sides

= sqr(6^2 +6^2) = sqr(36+36) = sqr72 = 6sqr2

sinA= 6/6sqr2= 1/sqr2= sqr2/2

cscA=1/sinA= 2/sqr2= sqr2

but if you really meant opposite & adjacent angle = 6 degrees and a right triangle (given a hypotenuse) then it's an impossible 90-6-6 angled triangle

still A would seem to be the 90 degree angle

then sinA=1=cscA

cosA=0

secA= is undefined

tanA is undefined

cotA=0

as written the problem makes no sense