Write an equation in slope-intercept for a line that passes through (6,2) and is parallel to y = -2/3x + 1.

Answer 1

Parallel lines have the same slope, The slope of the line with equation y = (-2/3)x + 1 is -2/3.

So, an equation of the desired line is y - 2 = (-2/3)(x - 6).

Simplifying, we get y = (-2/3)x + 6.

Answer 2

y-2 = (-2/3)(x-6) in point slope form

y = (-2/3)x + 6 in slope intercept form

slope = -2/3

y intercept = 6

check the answer, plug in the point (6,2)

2=(-2/3)(6) +6 = -4+6=2