Write an equation in slope-intercept form for the line that passes through (−3, 2) and is perpendicular to y=12 x+9 .

Answer 1

y-2 =(-1/12)(x+3) in slope intercept form for a perpendicular line through (-3,2)

perpendicular lines have negative inverse slopes. negative inverse of 12 = -1/12. Just change the sign and flip it upside down.

x+12y = 21 in standard from

y = (-1/12)x + 7/4 in slope intercept form

x+12y-21 = 0 in general form