If sin(θ) = x/11, then cos(θ) = sqrt(1-x2/121)
cos(2θ) = cos2(θ)-sin2(θ) = (1-x2/121) - x2/121
tan(θ/2) = +/- (1 - cos(θ))/sin(θ) (This form is easier to deal with than sqrt((1-cos(θ))/(1+cos(θ))
Please consider a tutor. Take care.
Alison C.
asked 12/05/22Assume sin(θ)=x/11 where 0<θ<π/2. Compute the following in terms of x.
cos(2θ)=
tan(θ/2)=
If sin(θ) = x/11, then cos(θ) = sqrt(1-x2/121)
cos(2θ) = cos2(θ)-sin2(θ) = (1-x2/121) - x2/121
tan(θ/2) = +/- (1 - cos(θ))/sin(θ) (This form is easier to deal with than sqrt((1-cos(θ))/(1+cos(θ))
Please consider a tutor. Take care.
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