
Dayv O. answered 12/03/22
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
1/sin(x)=[cos(x)/sin(x)]-1
1=cos(x)-sin(x),,,,,,,,x=0+2πk not valid for answer since sin(0+2πk)=0 and 1/sin(x) is not valid
cos(x)-sin(x)=√2*cos(x+π/4),,,,,important identity, -π/4=tan-1(-1/1)
x+π/4=cos-1(√2/2)+2πk
and
x+π/4=-cos(√2/2)+2πk
from first equation, x=0 which is not available for valid answer
from second equation
x=-π/2+2πk,,,,k=0,+/-1,+/-2,...