Find all the angles between 0 and 360 degree inclusive which satisfy the equation. (i) sin (2x+15 degree)= -0.5

Answer 1

sin(2x+15) = -.5

reference angle = 30 degrees, in quadrants III or IV where sines are negative

2x+15 = 210, 330 or 570 or 690 degrees

go any higher and x will be greater than 360

2x = 195 or 315 or 555 or 675

x = 97.5, 157.5, 277.5 or 337.5 degrees